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Probability question...
40 yard dash statistics below.
Alf has a Avg of 4.42 with a stddev of .04 Bob has a Avg of 4.43 with a stddev of .04 Charlie a Avg of 4.45 with a stddev of .04 Dave's Avg is 4.47 with a stddev of .04 Is the probability that Alf beats Bob = Normsdist(.01/.04), or 59.87%? (.7733 for Alf vs Charlie, .89435 for Alf vs Dave) If that is so, what is the probabilty that Alf wins a race with all 4 of them running? Do i have to monte carlo this? I am thinking i cant take .5987*.7733*.89435 to get to an answer. |
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