#1
|
|||
|
|||
5 handed, 5 pocket pairs dealt-- odds of no flopped sets?
If in a 5 handed game 5 different pocket pairs were dealt, would this be the way to go about calculating the odds of no one flopping a set?
( nCr(10,0) * nCr(32,2) )/ ( nCr(42,3) ) which comes out to equal : 4.3206% |
|
|