Approximating Multiple Opponents

[pzhon]

A simpler counterexample would be to consider AK vs. two low pairs. AK wins under 50% against either, but almost 40% against both.

[Carl_William]

Dear Gamey Mouse

Your are correct -- at least I got same answer as you did of 35%. I used a brute force counting scheme (numerical enumeration). Three players: A, B, & C. A beats B 70% of the time; & A beats C 30% of the time. 100 permutations covers all possible cases.

Evidently you solved it the easy way. I did it using brute force on an excel spreadsheet -- what a waste if time my way was....