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#1
02-09-2005, 06:18 PM
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HU nl 25c/50c.... JJ,AA,AA, in a row
game on prima, heads up NL, he had JJ, AA, AA in a row, is there anyway to calculate the odds of that occuring? thanks
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#2
02-10-2005, 06:35 AM
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Re: HU nl 25c/50c.... JJ,AA,AA, in a row
a specific pocket pair is 1/221 ... so that exact sequence is (1/221)^3 = 10.8 mil : 1
The odds of getting 3 straight broadway pockets is ((20/52)*(3/51))^3 = 86350:1 Yesterday I got JJ 4 hands in a row, the odds of someone getting the same pocket 4 hands in a row is around 180 mil to 1, theres a post about it in here
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