#11
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Re: A post for Ed Miller
this is where I'm confused, I'm working these out myself now...... why am I using (8/47) x (8/46)..... shouldn't it be 8/47 x 7/46 ?
I don't understand. |
#12
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Re: A post for Ed Miller
this is where I'm confused, I'm working these out myself now...... why am I using (8/47) x (8/46)..... shouldn't it be 8/47 x 7/46 ?
(8/47)(8/46) represents: Eight cards on the turn give you an open-ended straight draw. Eight cards on the river complete that open-ended straight draw. When two terms are summed, it indicates that they are mutually exclusive. |
#13
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Re: A post for Ed Miller
thanks Ed, I got it now.
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#14
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Re: A post for Ed Miller
If the turn is a Queen or a 8, you will have either four Kings and four 8's or four Queens and four 7's to make your backdoor straight. Which is 8 outs on the turn and 8 outs on the river.
If the turn is a King or a 7, you will have either four Queens or four 8's to make you backdoor straight. Which is 8 outs on the turn and 4 outs on the river. This can then be broken down into: (8/47)(8/46) + (8/47)(4/46) = 96/2162 = 4.4% To break that into odds: 100 - 4.4 = 95.6 95.6/4.4 = 21.72 or 21.7 to 1 odds If I did the calculations correctly, you will catch two runners to make a backdoor straight a little more than 4% of the time or 21.7 to 1 odds. Hope this helped and I hope it is correct, it's awfully late and I'm a wee bit tired. [img]/images/graemlins/cool.gif[/img] |
#15
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Re: A post for Ed Miller
LOL, should have read farther down the thread before I did the calculations AGAIN for ya. Sorry about that did not know Ed had done them for you already.
[img]/images/graemlins/cool.gif[/img] |
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