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  #1  
Old 12-12-2004, 09:31 AM
AA suited AA suited is offline
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Default Heads up: % of the time high card wins?

Final 2 in SnGs.

What % of the time does the person w/the high card win played to showdown? (ie: board helps neither person)

thx
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  #2  
Old 12-12-2004, 01:00 PM
Paul2432 Paul2432 is offline
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Default Re: Heads up: % of the time high card wins?

This question is impossible to answer. For each matchup the answer will be different (between 50-75%)

Paul
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  #3  
Old 12-12-2004, 05:38 PM
gaming_mouse gaming_mouse is offline
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Default Re: Heads up: % of the time high card wins?

Well, not impossible to answer, but a pointless and uninformative exercise for sure. I mean you could write a program to enumerate over all possible matchups, which would count the number of times the person with the high card wins.

But this is surely not what the OP really wants to know. I'd guess there are certain situations (hand types) that he's interested in. But who knows.

AA Suited, could you clarify?

gm
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  #4  
Old 12-13-2004, 01:10 AM
AA suited AA suited is offline
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Default Re: Heads up: % of the time high card wins?

when heads-up, what % of the time does the board (flop/turn/river) not help either player?
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  #5  
Old 12-13-2004, 02:15 AM
gaming_mouse gaming_mouse is offline
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Default Re: Heads up: % of the time high card wins?

Without some more assumptions about the 2 players hands it becomes a pain to calculate, and not too useful either. So let's assume that neither player has a pocket pair, and that players share no cards. That is, between the two players there are a total of 4 different card ranks. In that case, the chance that neither player pairs by the river is:

(36 choose 5) / (48 choose 5) = 0.220166512

gm
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  #6  
Old 12-13-2004, 06:23 PM
AA suited AA suited is offline
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Default Re: Heads up: % of the time high card wins?

[ QUOTE ]
Without some more assumptions about the 2 players hands it becomes a pain to calculate, and not too useful either. So let's assume that neither player has a pocket pair, and that players share no cards. That is, between the two players there are a total of 4 different card ranks. In that case, the chance that neither player pairs by the river is:

(36 choose 5) / (48 choose 5) = 0.220166512

gm

[/ QUOTE ]

exactly what i was looking for.

22% seems like a low # though? That means 39% of the time one person will pair up. Thus the person with the high card has a 22+39 = 61% chance of winning?
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  #7  
Old 12-13-2004, 01:18 AM
joeboss joeboss is offline
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Default Re: Heads up: % of the time high card wins?

ill take a stab at it...
the chances of pairing are 6/50 + 6/49... ect...
thats about 62.55% of course this is not including flushes ect...
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  #8  
Old 12-13-2004, 08:26 AM
yoshi_yoshi yoshi_yoshi is offline
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Default Re: Heads up: % of the time high card wins?

As a rough estimate, I ran this through the twodimes poker analyzer...

Hands:
As 7c
Jh 3s
2c 2s

Dead Cards: 2d 2h

Results:
cards EV
As 7c 0.489
3s Jh 0.369
2s 2c 0.141

This has the effect of a twelve-card deck (since all the 2s are gone) and I've chosen two hands that minimize straight/flush possibilities.

So based on a twelve-card deck, the odds of one of the two players hitting something is approx. 85%. For a regular 13-card deck, you could estimate it at 75-85% I think.

What about hole cards that work together more? I also ran...

cards EV
6s 5s 0.347
Jc Tc 0.567
2s 2c 0.086 (dead cards: 2d 2h)

So with two suited connectors, one of them will hit something in a 12-rank deck a good 93% of the time, meaning 85-90% in a regular deck.
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