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  #1  
Old 01-28-2005, 12:46 PM
elwoodblues elwoodblues is offline
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Default Math question (maybe our resident rocket scientist can help)

This has always bothered me. I think it is just trying to wrap your head around infinity, but any help from anyone would be appreciated.

Does .999999(repeating) really = 1? I think it's just really, really (repeating) close, but the below suggests otherwise:

1/9 = .11111(repeating)
1/9 x 9 = 1
.11111(repeating) x 9 = .99999(repeating)
Therefore .99999(repeating) = 1
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  #2  
Old 01-28-2005, 12:49 PM
ThaSaltCracka ThaSaltCracka is offline
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Default Re: Math question (maybe our resident rocket scientist can help)

I think a really anal math teacher will tell you .9999999 does not actually equal one.
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  #3  
Old 01-28-2005, 12:50 PM
Tron Tron is offline
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Default Re: Math question (maybe our resident rocket scientist can help)

They are just different ways of writing the same thing.
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  #4  
Old 01-28-2005, 12:52 PM
GuyOnTilt GuyOnTilt is offline
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Default Re: Math question (maybe our resident rocket scientist can help)

Any middle school level math text would be able to tell you this. I'm sure you've read it in reliable sources before, so why are you still asking? The answer is still yes.

GoT
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  #5  
Old 01-28-2005, 12:54 PM
Mano Mano is offline
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Default Re: Math question (maybe our resident rocket scientist can help)

That is correct, there is no difference between .9999... and 1 ( i.e. 1 - .9999... = 0).
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  #6  
Old 01-28-2005, 12:56 PM
elwoodblues elwoodblues is offline
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Default Re: Math question (maybe our resident rocket scientist can help)

[ QUOTE ]
I'm sure you've read it in reliable sources before, so why are you still asking? The answer is still yes.


[/ QUOTE ]

I "know" the answer is yes because people have told me and I can "prove." I just have a hard time wrapping my head around it. My mind tells me that they aren't equal and that they have a difference of .0000(repeating)1.
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  #7  
Old 01-28-2005, 01:00 PM
TimM TimM is offline
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Default Re: Math question (maybe our resident rocket scientist can help)

[ QUOTE ]
I "know" the answer is yes because people have told me and I can "prove." I just have a hard time wrapping my head around it. My mind tells me that they aren't equal and that they have a difference of .0000(repeating)1.

[/ QUOTE ]

The repeating zeros are infinite in number, so you never get the 1.
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  #8  
Old 01-28-2005, 01:53 PM
junkmail3 junkmail3 is offline
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Default Re: Math question (maybe our resident rocket scientist can help)

[ QUOTE ]
[ QUOTE ]
I "know" the answer is yes because people have told me and I can "prove." I just have a hard time wrapping my head around it. My mind tells me that they aren't equal and that they have a difference of .0000(repeating)1.

[/ QUOTE ]

The repeating zeros are infinite in number, so you never get the 1.

[/ QUOTE ]

This is correct. Otherwise, what would be the point of haveing a number that is .9999999999999999... and a number that is 1.

if they are the same thing, call them the same thing. You will approach 1 (and for many applications can call it one) but it is not turely 1. Ever.
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  #9  
Old 01-28-2005, 03:13 PM
anisotropy anisotropy is offline
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Default Re: Math question (maybe our resident rocket scientist can help)

[ QUOTE ]
1/9 = .11111(repeating)

[/ QUOTE ]
incorrect. The decimal form is an approximation of an irregular number.
[ QUOTE ]
1/9 x 9 = 1

[/ QUOTE ]
correct
[ QUOTE ]
.11111(repeating) x 9 = .99999(repeating)

[/ QUOTE ]
correct
[ QUOTE ]
Therefore .99999(repeating) = 1

[/ QUOTE ]
incorrect
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  #10  
Old 01-28-2005, 03:32 PM
BeerMoney BeerMoney is offline
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Default Re: Math question (maybe our resident rocket scientist can help)


Let
n=.9999999999999999...
10n=9.9999999999999999.....
10n-n = 9
9n = 9
n = 1

It is wierd. I guess our number system is messed up.
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