Math question (maybe our resident rocket scientist can help)

[Patrick del Poker Grande]

Let's not forget this little gem:

a = x
a+a = a+x
2a = a+x
2a-2x = a+x-2x
2(a-x) = a+x-2x
2(a-x) = a-x
2 = 1

[Sporky]

i believe your logic is flawed.

[DMBFan23]

what we're actually saying is that 1 - [1 - {1/(10*n)}] tends to 0 as n tends to infinity.

1 - 0.9
1 - 0.99
1 - 0.999


...


1- 0.9999999999999

etc.

so since A minus the limit of B equals 0, the limit of B = A. but limit of B = 0.99999999999999......

[BeerMoney]

[ QUOTE ]
i believe your logic is flawed.

[/ QUOTE ]
There's nothing wrong with it at all.. ITs the way you convert a repeating decimal to fraction..

eg..

n = .27272727......
100n =27.2727272727

100n -n = 27
99n = 27
n=27/99

27/99 = .2727272727272727

Or, how about an infinite geometric sum..

.999999999999= .9+.09+.009 +.0009 etc..
= sum .9*.1^n let n -> infinity= sum a*r^n where a = .9, r = .1.. = a/(1-r) = .9/(1-.1) = .9/.9 = 1

[Patrick del Poker Grande]

This thread blows. Next.

[pudley4]

[ QUOTE ]
Let's not forget this little gem:

a = x
a+a = a+x
2a = a+x
2a-2x = a+x-2x
2(a-x) = a+x-2x
2(a-x) = a-x
2 = 1

[/ QUOTE ]

Can't divide by zero (a-x = 0)

Sheesh, they don't make rocket scientists like they used to...



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