Quck counting question

[rex4334]

I've read that given 2 suited cards hole cards your chances of improving to a 4 flush by the flop is 10.9 percent. I'm trying to verify this for myself mathematically. Given that C(n,r) is the number of r-combinations of a set with n-elements does the following make sense?

P(x) = ( C(11,2) * (50 - 11) ) / C(50,3)

Where P(x) is the prob. of drawing 3 more cards from the remaining 50 cards and improving to a 4-flush, given that you are delt 2 hole cards of similar suit

Thx