#1
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Poker Probability Problem Post
was doing some thinking. need some verification (if right) and correction (if wrong)
there are 8 ways to make a pocket pair, and 16 ways to make any 2 unsuited cards. I take a sample of top hands let's say.... AA KK JJ AK (suited or unsuited) AQ (suited or unsuited) now,,, you have 3 pocket pairs for 4x8=32 combinations and you have 2 off rank hands 16x2= 32 so the total is 64 there are 1326 combinations for hands,,,, 64/1326=.0482 lets round up to .05 for arguments sake. this means that the chances of getting dealt on of these hands is (about) 5% and this also means that the chance of any person at a 10 person table having one of these hands is (.05x10) or %50 this means that once in every 2 rounds at a full table, you will get dealt one of these hands. is this correct? becuase it seems like hands like that don't come around that often. please correct me if i am wrong. thanks |
#2
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Re: Poker Probability Problem Post
there are 6 ways to have a pocket pair, 12 ways to have unsuited cards (not counting pairs) and 4 ways to have suited cards.
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#3
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Re: Poker Probability Problem Post
correct,
also, another general rule of thumb I have heard is that at a 10 handed table, at least 1 person will have a pp. I have read ur odds of getting aces are 1/6500. |
#4
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Re: Poker Probability Problem Post
[ QUOTE ]
correct, also, another general rule of thumb I have heard is that at a 10 handed table, at least 1 person will have a pp. I have read ur odds of getting aces are 1/6500. [/ QUOTE ] You're a gimmick, right? Aces are 1 in 221. You have a 1 in 17 chance of being dealt a pair, and 1 in 13 of those are aces. |
#5
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Re: Poker Probability Problem Post
Furthermore, the odds of no one having a PP =
(1- 1/17)^10 = 54% |
#6
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Re: Poker Probability Problem Post
[ QUOTE ]
[ QUOTE ] correct, also, another general rule of thumb I have heard is that at a 10 handed table, at least 1 person will have a pp. I have read ur odds of getting aces are 1/6500. [/ QUOTE ] You're a gimmick, right? Aces are 1 in 221. You have a 1 in 17 chance of being dealt a pair, and 1 in 13 of those are aces. [/ QUOTE ] I wouldn't questions his knowledge. He's read every poker book there is! |
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