think about this...

[Patrick del Poker Grande]

[ QUOTE ]
If you are saying that the runway moves backward at the speed the wheels’ center of mass translates forward, the plane is not moving forward with respect to the air, and will never take off.

If the runway moves backward at the tangential speed at which the edge of the wheels move, then the plane can achieve forward movement with respect to the air, and presumably take off.

The plane moves a distance d equal to the circumference of its wheels in time t. The time t is the period of rotation of the plane’s wheels, which is equal to 1/w, the angular speed of the wheels’ rotation.

Vplane=(2*pi*rwheel)*w

Omega is equal to the speed of the edge of the wheel divided by their radius by geometry.

Vedge=rwheel*w

Thus, Vplane=2*pi*Vedge.

So the plane speed with respect to the air = Vplane-Vrunway = Vplane-Vplane/(2*pi) = Vplane*(1-1/(2*pi)). (Vplane is the speed of the plane with respect to the runway...)

[/ QUOTE ]
I hope you had fun doing all this crap.