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# of Omaha Starting hands
Not exactly probability but,
how many starting hands are possible in omaha if suits are not taken into account (like how they are listed in PTOmaha)? So that A [img]/images/graemlins/spade.gif[/img] A [img]/images/graemlins/diamond.gif[/img] 2 [img]/images/graemlins/spade.gif[/img] 3 [img]/images/graemlins/diamond.gif[/img] and A [img]/images/graemlins/heart.gif[/img] A [img]/images/graemlins/club.gif[/img] 2 [img]/images/graemlins/heart.gif[/img] 3 [img]/images/graemlins/club.gif[/img] are counted as the same hand. Im not familiar with this kind of math, but my initial guesses were: 13*12*11*10 or 13^4 but i really am not sure. If you do know how to figure this out, could you please explain it for me. Thanks in advance cielo |
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