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  #11  
Old 03-23-2005, 06:59 PM
irchans irchans is offline
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Join Date: Sep 2002
Posts: 157
Default Re: Question about game

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What happens when player 1 chooses 1 and player 2 chooses 200?

According to the rules as stated,

player 1 pays player 2 100-200+1 = -99.

Does that mean player 2 pays player 1 99?

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yep

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Then I could not afford to play the game. Suppose I bid 121 and my opponent bids 1,000,000. Then

He pays me 100-(1000000)+121 = -999779.

Thus I pay him 999779.

Basically, if one player bids x then the other player can win 1000 or more by bidding x+1100 or more.

It seems that if you were forced to play the game, then you should bid the largest number you can imagine.

Am I missing something here?
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  #12  
Old 03-23-2005, 07:15 PM
jimdmcevoy jimdmcevoy is offline
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Posts: 728
Default Re: Question about game

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He pays me 100-(1000000)+121 = -999779.

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nah small pays big
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  #13  
Old 03-24-2005, 03:03 PM
jedi jedi is offline
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Join Date: Oct 2003
Posts: 517
Default Re: Question about game

[ QUOTE ]
Then I could not afford to play the game. Suppose I bid 121 and my opponent bids 1,000,000. Then

He pays me 100-(1000000)+121 = -999779.

Thus I pay him 999779.


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the player who picked the smaller number pays the other player 100-L+S cents (negative meaning he recieves money instead of paying)


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In your example, the smaller player (121) would pay the bigger player (1,000,000) 100-1,000,000+121 = -999,779 Negative number means the smaller player would receive $999,779. Right?
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  #14  
Old 03-24-2005, 03:56 PM
Paul2432 Paul2432 is offline
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Join Date: Jun 2003
Location: Bryn Mawr, PA USA
Posts: 374
Default Re: Question about game

Right. If you pick is less than 200 you can never lose more than 99 cents.

Paul
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