#11
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Re: Question about game
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[ QUOTE ] What happens when player 1 chooses 1 and player 2 chooses 200? According to the rules as stated, player 1 pays player 2 100-200+1 = -99. Does that mean player 2 pays player 1 99? [/ QUOTE ] yep [/ QUOTE ] Then I could not afford to play the game. Suppose I bid 121 and my opponent bids 1,000,000. Then He pays me 100-(1000000)+121 = -999779. Thus I pay him 999779. Basically, if one player bids x then the other player can win 1000 or more by bidding x+1100 or more. It seems that if you were forced to play the game, then you should bid the largest number you can imagine. Am I missing something here? |
#12
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Re: Question about game
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He pays me 100-(1000000)+121 = -999779. [/ QUOTE ] nah small pays big |
#13
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Re: Question about game
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Then I could not afford to play the game. Suppose I bid 121 and my opponent bids 1,000,000. Then He pays me 100-(1000000)+121 = -999779. Thus I pay him 999779. [/ QUOTE ] [ QUOTE ] the player who picked the smaller number pays the other player 100-L+S cents (negative meaning he recieves money instead of paying) [/ QUOTE ] In your example, the smaller player (121) would pay the bigger player (1,000,000) 100-1,000,000+121 = -999,779 Negative number means the smaller player would receive $999,779. Right? |
#14
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Re: Question about game
Right. If you pick is less than 200 you can never lose more than 99 cents.
Paul |
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