Two Plus Two Older Archives  

Go Back   Two Plus Two Older Archives > General Gambling > Probability

Reply
 
Thread Tools Display Modes
  #1  
Old 08-04-2005, 06:46 AM
bobhammock bobhammock is offline
Junior Member
 
Join Date: Aug 2005
Posts: 1
Default Archived thread - inclusion-exclusion example

Hi all,

This forum seems great.

My question is very specific and concerning an archived thread with BruceZ in the drivers seat:
http://archiveserver.twoplustwo.com/...art=1&vc=1

In Brucez's answer it follows:
" C(8,2)* 78/C(52,2) * 73/C(50,2) = 9.8%. C(8,2) is the number of ways to pick the 2 players. There are 73 pairs remaining after the first player chooses a pair"

- Now, why are there 73 pairs left after 1st player chooses a pair? I know we can't just pick from 12 ranks and pretend that the 2nd player can't pick a pair of the same rank as the first. But why 73...?

I want of course to be able to make the next term myself.

ty.
Reply With Quote
Reply

Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off

Forum Jump


All times are GMT -4. The time now is 02:00 AM.


Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2024, vBulletin Solutions Inc.