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#1
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Re: Help Calculating The Odds on this Roulete Bet
In the long run, 24/37 times you'll "win" $100. If it hits on 14, you bet $200 but you take back $300 for a profit of $100. Make sense?
In the long run, 13/37 times you'll lose $200. This should be obvious. 25-36 and 0. Make sense? Edit: Yes, you will win more often than you lose (64.86% of the time). You'll just lose twice as much money as you win. |
#2
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Re: Help Calculating The Odds on this Roulete Bet
yeah that makes sense now thanks.
Well what do u think of my idea. Im gonna bet $100 dollars on 1st 12 and $100 dolalrs on 2nd 12. If i win 10 times in a row spliting the profit won between the 2 bets. I'll make 1135 by wining 7 bets in a row. I dunno that doesnt sound to bad. Better yet just bet on black or red. if i bet 100 dollars i get back 1:1 if i double it up each time i win if i win 10 times in a row thats $52,000 dollars |
#3
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Re: Help Calculating The Odds on this Roulete Bet
For your sake, I hope you're just being a troll.
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#4
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Re: Help Calculating The Odds on this Roulete Bet
Maybe it is better to bet 100$ on the first 12 and 100$ on the last 12. Make sense?
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#5
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Re: Help Calculating The Odds on this Roulete Bet
why would that be a better bet
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#6
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Re: Help Calculating The Odds on this Roulete Bet
Because you win only 24/37 if you bet on the first two columns, of course. So, the rest must be on the last one. That would give you a rock solid advantage!!1
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