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Re: Combinations of Pairs of Gloves..halp
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The "Expected number of pairs picked = 10 * the chance that any given pair is picked" argument is correct. The chance of picking one particular pair, however, is 18C4 / 20C6 = 3060 / 38760, rather than the number quoted by the other responders. [/ QUOTE ] Damn all those other responders, how could they all have missed that? [img]/images/graemlins/grin.gif[/img] I would have figured that out when I fixed the combinatorics in the original post, which I still plan to do later tonight. Edit: Looks like you already found the combinatoric problem. |
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