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#1
03-22-2005, 11:42 AM
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Easy probability question...
Right. I got a probabilty question with very important practical implications. My university exams are coming up very soon, and an answer to this question would help me in my revisions.
The known facts: - There are 10 lectures in each course. - Our exams for each course will consist of 7 essay questions of which we have to answer 2. - The 7 essay questions will cover a minimum of 6 lectures (ie 2 questions could be on the same lecture) My question is: How many lectures should I revise so that I am 95% sure that at least 2 questions out of 7 I will have covered in my revision? What about if I take a bigger risk and make that 85%? P.S.: I'm obviously not a math student [img]/images/graemlins/grin.gif[/img] Ta 
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#3
03-22-2005, 02:18 PM
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Re: Easy probability question...
Brilliant. I'm quite surpised that there is such a big gap in chances of success between 3 & 4 lectures... If your calculations are right, it means that studying 4 lectures has the best work : result ratio. Which means the best strategy would be to revise 4 lectures for each course & then revise the rest if time permits.
Thanks for your help.
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#5
03-22-2005, 04:51 PM
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Re: Easy probability question...
I've revised the numbers. These numbers I am much more confident. Instead of a calculation, I simply listed all the possible calculations and then counted. (made easy using MS Excel, I can e-mail you the file if you like).
Number lectures studied / Chance of success 1 / 9% 2 / 43% 3 / 76% 4 / 91% 5 / 98% 6 / 100% Paul
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#6
03-22-2005, 04:51 PM
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Re: Easy probability question...
I've revised the numbers. These numbers I am much more confident. Instead of a calculation, I simply listed all the possible calculations and then counted. (made easy using MS Excel, I can e-mail you the file if you like).
Number lectures studied / Chance of success 1 / 9% 2 / 43% 3 / 76% 4 / 91% 5 / 98% 6 / 100% Paul
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Linear Mode
