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#1
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Re: What are the odds of 100 hands no PP?
Bruce, I know this isn't my question, but I was wondering if you could provide any information as to what those numbers mean? Like where do you get the 16/17 and such...thanks a bunch
Trying to learn, TheProdigy |
#2
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Re: What are the odds of 100 hands no PP?
The chance of getting a PP is 1/17, so the chance of not getting a PP is 16/17. The chance of something happening n times in a row is x^n, where x is the probability of the event. The chance of not getting a PP 100 hands in a row is then (16/17)^100.
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#3
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Re: What are the odds of 100 hands no PP?
[ QUOTE ]
Bruce, I know this isn't my question, but I was wondering if you could provide any information as to what those numbers mean? Like where do you get the 16/17 and such...thanks a bunch Trying to learn, TheProdigy [/ QUOTE ] The probability of being dealt a pair is 52/52 * 3/51 = 1/17, so 16/17 is the probability of not getting dealt a pair. The probability of not getting a pair 100 times in a row is (16/17)^100. |
#4
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Re: What are the odds of 100 hands no PP?
If you have trouble understanding where it comes from, stick with the raw numbers:
(Any first card, or 52 out of 52) and (a non-pairing second card, which is 48 cards out of the remaining 51) (52/52) * (48/51) .9411765 94.11765% 100 times in a row: .9411765 * .9411765 * .9411765 * [. . .] * .9411765 .9411765^100 .002329 .2329% |
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