A Pure Math Situation

[sk_man]

My numbers came out a little diffent than yours. I tried it both with and without TT, because I'm not sure if I would eliminate them.

AK - 9
AA - 3
KK - 3
QQ - 6
JJ - 3
TT - 6

Drawing Dead: JJ and AA, 6 combos, EV -2
6 outs: TT and QQ, 12 combos, EV -.2681
6 outs (without TT): QQ, 6 combos, EV -.2681
3 outs: KK, 3 combos, EV -1.1341
Tied: AK, 9 combos, EV 4.35

Then we just average each situation weighted by the number of combos, and that should give us our EV for the hand.

Including the TTs, I came out with .6843, and without them, it was .92245. Still a call down, but if we start to discount AK, then it becomes very close.

To get the EV, I was taking the odds that the hero will win the hand, multiplying it by the size of the pot (at the end of the hand) and subtracting the amount we have to call to see the showdown.

EV = O*(P + 4) - 2

This might be a little off, because there's a good chance villian would check through TT and maybe QQ on the river. So, in that case the EV would be:

EV = O*(P + 2) - 1

I don't really care about the exact numbers. I just want to know, if I'm doing this right.