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Old 02-16-2005, 11:04 AM
twistedbeats twistedbeats is offline
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Join Date: Sep 2002
Location: Beatdown Town, Antarctica
Posts: 156
Default Proposition bet - 2 cards next to each other in a pack

i just flat out don't know how to calculate this one. the bet is choose one card rank, 2 through ace. choose another. search through the pack. at least one of card rank a will be touching card rank b. my initial way of calculating was saying that for every card there are 47 cards that don't win the bet before the card and 46 cards after, so the probability is 1 - [(47/51)^8 * (46/51)^8] but that doesn't take into account the the times either card a or card b are on the ends of the deck, plus it just doesn't look right. any help is appreciated.
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