Don't Use Formula For This

* Using simple fractions and simple logic, tell me how to calculate the chances of gettiing, (when tossing five dice, five times), exactly one three exactly one toss (the other tosses result in 0,2,3,4,or 5 threes). * ... call it p


... when tossing 25 dice, one time ... call it p1


... when tossing one dice, 25 times ... call it p2


... when tossing one dice, 25 times ... gettiing exactly one three in the 7th toss ... call it p3


p3= (5/6)^24*(1/6)


p2=25*p3


p1=p2


p=p1


p= (5/6)^24*(1/6)*25= 5,24 %

Jack has lost his mind or he can't read !?


brad and Bruce got it right.