#21
|
|||
|
|||
Re: Two Questions
Just a) for now. Let P(n)= the probability of throwing a pair of dice n times w/o throwing a seven. P(n)={5/6}^n Now P(3)> 1/2 while P(4) |
#22
|
|||
|
|||
question A is misleading.
question a is misleading. it can be interpreted as: 'how many times must you throw 2 dice that the next throw is more likely than not to be a 7?' or as 'how many times must you throw 2 dice so that you will be more likely than not to have thrown a 7 in that sequence?' |
#23
|
|||
|
|||
Re: question A is misleading.
1. Never 2. 20,000 If the chances are 1 out of 40,000 then half the time i will hit it before 20,000 and half the time I will hit it after 20,000. |
|
|