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Help Figuring Out Odds
Just for kicks and mental exercise, last night I tried to calculate the odds of flopping an open-ender in hold'em, given the starting hand of 67. To simplify my calculations, I didn't worry about "accidentally" getting a real straight.
I got stuck after awhile, and couldn't figure it out. Help on my thinking process would be appreciated. There are three sets of two cards that give me an open-ender (45, 58, 89). Each of the three is equally likely. Thus I figured that the answer was: Let P(OE) = Probability of flopping one of the three success hands. ( 3 * P(OE) ) / (50c3) This seems fairly obvious to me. However I'm having trouble finding P(OE). I don't particularly want an answer to what P(OE) is, but just a hint or two on where to go next. Thanks. |
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