Mistake in Harringtons second edition??

I am not sure what forum to put this in, but since it applies to super satellite play, ill try this one.

I think I found a formula error in Harrington's second edition p 422. I believe his formula is a "close" aproximation for this case and many others, but suppose we change the problem slightly and say instead of 6 people left there are only 5, but one of them has 9000 in chips. His equation would then read

x + x + 4.5x + 4.5x + 9.0x = 400.

x would still equal 20, but now our 9000 chip player would have 180% chance of qualifying. This of course can't be. So did i make a mistake, or is this an old problem that has been solved, or does anybody know the proper formula, (assuming all are equal skill levels)? I have some ideas of a formula, but it is somewhat complicated and I wanted to know if the problem has already been solved, (or I am missing something here),

Thanks,
Puppy Toes

[yvesaint]

theres a mistake in harringtons second edition ??? whoa

techinically, he can't be knocked out by anyone, so it seems like the 'extra' 100% form some sort of extra life. if he loses an all in to the 4.5x stacks, then he goes back down to 85% himself.

The Independent Chip Model is probably better for modeling stuff like that (http://sharnett.bol.ucla.edu/ICM/info.html).

That gives the 9x chip stack a 99.1% chance of qualifying.

[burningyen]

There is a HOH2 errata list in the Books/Publications forum.

Thanks, i think you hit the nail on the head for me. I haven't finished "killing" the material yet, but from what i could see so far, it was just about what i was thinking and i thought it wasn't a "simple" formula. It has links to computer code as well. excellent thanks!

thanks, i didn't see a reference to this particular problem there, but I did make a copy to update my book! [img]/images/graemlins/smile.gif[/img]