Party Poker Sidebets

[BruceZ]

[ QUOTE ]
EV = $8 *(1/8.5) - 1 *(7.5/8.5) = .94 - .88 = -6.25%

[/ QUOTE ]

EV = $7 *(1/8.5) - 1 *(7.5/8.5) = -5.88%

The payout is 8 FOR 1, which means 7 TO 1, not 8 TO 1. Otherwise it would be +EV.

Thanks all, this "8 for 1" explanation makes everything clear.

That is very sneaky of them.

[TomCollins]

I stoopid.

[kelvin474]

Bruce,

In addition to craps, this sneakiness happens in video blackjack. "All winning hands pay 2 for 1". "Blackjack is an automatic winner and pays 2 for 1".

[RoundTower]

I haven't played this game, so I know very little about it, but I thought of this. I assume it is a push if there is no flop.

In that case if you have a significant chance of influencing whether there will be a flop or not, you could have an edge. For example: you bet $10k on all red in the .50-1 game, and you are dealt two red aces in the big blind. Someone raises, and it is folded around to you. You fold. If you were dealt 9 [img]/images/graemlins/club.gif[/img] 4 [img]/images/graemlins/spade.gif[/img], you would call.

Right?

I like you're thinking, but unfortunately the maximum sidebet is 1BB on the 10$ SNGs. You could never gain enough leverage to make up for giving up the ev of pushing to prevent flops.

If you could selectively place bets after you've seen your 2 cards, I get a +ev of about 6.1%

[TomCollins]

It seems like you could collude to rip this game off real easily.

If you got a team of 10 players, all bet red. If the count of red cards is < x, see the flop. If not, someone raise and everyone else fold.

Getting ten people at a table to cooperate with each other doesn't sound real easy to me.

[yellowjack]

Sounds like a plan.

[TomCollins]

Find 10 friends, enter a tournament. I think you can even bet if you are watching too. Get 20 more friends to watch.