He is pushing any two or?

[se2schul]

[ QUOTE ]
the initial assumption wasn't that he would push 100% of hands

the initial assumption was that it is correct to push 100% and that villian KNOWS it's correct

we all do things that we know aren't correct at times, and villian is more likely to do an incorrect fold with 97 than with ak

[/ QUOTE ]

Well, of course if someone is going to play less than 100% of hands, they'd be rock stupid to play the worse hands and fold the better ones.

He's either playing any 2 or he's not. If he IS playing any 2, then AK is just as likely as 97 or 23. If he's NOT playing any 2, then out of any 2 hands that aren't pocket pairs, the better one is more likely.

Can the OP please clarify the assumptions???

[Nicholasp27]

yes, if he is playing any 2, then it's obviously a) unless hero has an a/k/9/7 in his hand (although one could make an argument that if 3 people folded before him, their likelyhood of holding a 9 or a 7 is greater than their likelyhood of holding an a or k, and therefore he is more likely to hold ak than 97 if he truly pushes any 2, even if it's a very small change in %)

however, the OP's assumptions are clear and he uses them in his argument of why it's not a)

the assumption is only that it is a +ev situation and that villian knows it's a +ev situation...the assumption is not that villian will take every +ev situation