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#21
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Hi Bruce.
I didn't get it with google, but I found it in Excel. It's actually not just C(x,y)= x!/y! It's C(x,y) = x!/y!(x-y)! I have a Casio fx-85M Scientific Calculator and I found a Combin function on there. It's labled nCr. I didn't even know what that function was before. Cool. Thanks, TomBk |
#22
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[ QUOTE ]
It's actually not just C(x,y)= x!/y! It's C(x,y) = x!/y!(x-y)! [/ QUOTE ] I know what it is, and I didn't say it was x!/y!. I said the numerator of C(x,y) = C(50,5) has y=5 terms counting down from x=50, so C(50,5) = 50*49*48*47*46/5! Note that this is 50!/(50-5)!/5! Note that the purpose of the (x-y)! in the denominator is to cancel with the last x-y terms in x!. So x!/(x-y)! = 50!/(50-5)! = 50*49*48*47*46. Then divide this by y! = 5! to get C(50,5) = 50*49*48*47*46/5! |
#23
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Ya OK. Thanks. Sorry.
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#24
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Like there are people setting in a poker game making those kinds of calculations in their head in a couple minutes or less! More likely they have memorized the odds and then only ball park except in the most trivial of cases...
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#25
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[ QUOTE ]
Specific odds for one suit/jackpot royal: 1. If you hold no hole cards for the royal: 2,118,670 (5/5 cards out of 50 cards left) 2. If you have 1 hole card: 46,060 (4/5 cards out of 50 left) 3. 2 hole cards: 1,960 (3/5 cards out of 50 left) So if the spade royal jackpot is up to $50,000 should you see the flop with any 1 spade 10 or higher? [/ QUOTE ] I'm glad to see this info, considering every time I go to my local casino I'm chastized by players for folding one card of the spade royal, which pays a progressive jackpot, usually between $10K and $40K. For that kind of money, the only time it would ever be correct to play, say, T[img]/images/graemlins/spade.gif[/img]2[img]/images/graemlins/heart.gif[/img] would be to complete a $0.50 small blind. Which brings me to my point: For a $50K jackpot, it's correct to call $1, and only $1, to see a flop with 1 card. At 1960:1, 2 cards of the royal makes a lot of jackpots I encounter +EV to play purely for the progressive, but since I'd play that kind of hand anyway, it's moot to me. At my local casino, they pay a flat $100 for lesser royals. Of course, it's never correct to play a hand for a shot at those royal jackpots. Another question: This casino also offers a progressive for a spade royal for Omaha 8, but since it (presumably) gets hit more, and since there are less omaha players, and thus a lesser rake, this jackpot is smaller - I've never seen it over $10K. What are the odds of hitting that jackpot, assuming a hand, of course, with exactly 2/5 of the royal? |
#26
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[ QUOTE ]
How it came up is. I was playing I floped the nut straight. With a gutshot to the royal. I missed the royal. It pays 1k to hit it. I made the comment that I have hit 2 royals in 200k hands online. a big debate followed afterwards as to how offten a royal is hit in hold'em. Lady told me 1 in `650k. I said it has to be more often that that. If i remeber correctly thats how often it is hit in draw poker. it happens more often in holdem due to the 7 cards. [/ QUOTE ] I hit my first ever royal- gutshot J last week on the turn with KQs. Managed to CR the river as well, there were a couple Ahigh straights out. Oh, and there was a $750 bonus. Which was nice. [img]/images/graemlins/cool.gif[/img] |
#27
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Keep in mind, the odds are different if you're talking about using both hole cards vs. using 1 vs. the board having a royal on it.
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#28
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[ QUOTE ]
C(3,3) * C(47,2) = 1081 The C(50,5) is right, so the third step should be: 1081/2118760 = 0.051% This is 1959:1 against, which still seems a little high. Maybe I'm making another mistake. [/ QUOTE ] The chance of getting suited broadways is like 0.030165913 The chance of making that into a royal flush is 0.000510204 or 1 in 64974 ok now if you hit the jackpot it makes you 49% of X and if someone else on the table hit you get 2.33% It cost you (.50*.60) or 3c a hand That would make 2700 the break even point of the High card jackpot correct? |
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