Cool Math/Logic Problem

[Bill Murphy]

No, its not a trick. I don't think I made a mistake in the initial post but I can check. Don't have the book here tho.

[pshreck]

yup, if thats a clue then Im feeling Ive been wasting my time being so interested in this.

[daryn]

</font><blockquote><font class="small">In risposta di:</font><hr />
yup, if thats a clue then Im feeling Ive been wasting my time being so interested in this.

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yup, but what did i expect?

[pshreck]

Bill, can you confirm that it's the right question. Can you answer it from all the info you gave? It seems like 1 small detail would be very important.

[Skjonne]

[ QUOTE ]
Nope!

[/ QUOTE ]

How about this then?

<font color="white"> 1760 </font>

[DBowling]

i got the same answer, damn, i guess ill have to think harder before reading any other's posts.

[Bill Murphy]

Alright, here it is(I knew I should've just copied it word for word).

The key is, when the ferries first pass each other, what's the total distance traveled by each? The width of the river, of course. Now, when they pass again, what's the total distance traveled? Three times the width, right? So, assuming constant speeds, the ferry that left Pier A has now traveled 720 yds x 3 = 2160 yds. And as its now 400 yds from Pier B the width of the river is 1760 yds or a mile.

[pshreck]

[ QUOTE ]
[ QUOTE ]
Nope!

[/ QUOTE ]

How about this then?

<font color="white"> 1760 </font>

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I got the same, answer, Im pretty positive thats it now.

[fatmongo]

** spoiler **
if anybody wants to check it out for themselves i googled and found it here . half way down the page

[Bill Murphy]

No, that had nothing to do with it. No tricks at all. *sigh* I knew it was a bad idea posting this, but I thought it was a neat lil' puzzle. Live &amp; learn.

Sam Loyd came up w/some insane chess problems, BTW.