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#21
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If you want to lock in the best deal for yourself, in that situation your opponent has 2 outs, so offer to run it 3 times.
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#22
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run the whole deck out.. now your EV is infinity!
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#23
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Hmm.. of course you're right, apparently I suck at math.
BTW I see term 3 as (1 - N/44) * N/43 which of course is indeed the same as term 2 : N/44 * (1 - (N-1)/43) though it's not obvious to me until you reduce them and see they are indeed equal. |
#24
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I believe that is only true for the case of running it twice. Remember that he was providing you the GENERAL solution. What is your point anyway? You know how to factor?
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#25
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I provided a general solution for running it twice. A truly general proof for running it n times with x outs and a deck of size q would be a worthy challenge.
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