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#22
07-22-2005, 02:34 PM
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Re: Sister\'s math problem X-post
[ QUOTE ]
[ QUOTE ] I think it is 3*(7+6+5+4+3+2+1)=84. [/ QUOTE ] Correct. [/ QUOTE ] Incorrect. You're counting triangles from one side to the other, but what about just counting the ones in the middle? There are a lot more than 84 there. 
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#23
07-22-2005, 02:34 PM
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Re: Sister\'s math problem X-post
[ QUOTE ]
[ QUOTE ] [ QUOTE ] I think it is 3*(7+6+5+4+3+2+1)=84. [/ QUOTE ] Correct. [/ QUOTE ] It's more. A lot more. C'mon jason_t. Are you stoned? [/ QUOTE ] No. No. No. No.
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#24
07-22-2005, 02:35 PM
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Re: Sister\'s math problem X-post
My first guess is 84, which is just the summation of x for 1-7 times 3. Times three beecause of the three sections of triangles.
PS. This place really needs to support LaTeX (for the 8th time). GoT
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#25
07-22-2005, 02:36 PM
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Re: Sister\'s math problem X-post
[ QUOTE ]
[ QUOTE ] [ QUOTE ] I think it is 3*(7+6+5+4+3+2+1)=84. [/ QUOTE ] Correct. [/ QUOTE ] Incorrect. You're counting triangles from one side to the other, but what about just counting the ones in the middle? There are a lot more than 84 there. [/ QUOTE ] I have no idea what you're talking about, but if you understood how the solution (7 + 6 + 5 + 4 + 3 + 2 + 1) * 3 is counting the triangles you would see that it's counting the "ones in the middle."
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#26
07-22-2005, 02:37 PM
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Re: Sister\'s math problem X-post
[ QUOTE ]
[ QUOTE ] [ QUOTE ] [ QUOTE ] [ QUOTE ] I think it is 3*(7+6+5+4+3+2+1)=84. [/ QUOTE ] Correct. [/ QUOTE ] It's more. A lot more. C'mon jason_t. Are you stoned? [/ QUOTE ] Are you sure? Remember a trapezoid is not a triangle. [/ QUOTE ] Yes. I'm sure. [/ QUOTE ] Here's is my reasoning. In the top tier there are 7 small triangles (triangle that cross zero lines). 6 triangles that cross 1 line. 5 that cross 2 lines. .... and 1 that crosses 6 lines. Each tier adds a new set of such triangles. Thus, the times 3 part. Please enlighten us as to yours?
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#27
07-22-2005, 02:40 PM
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Re: Sister\'s math problem X-post
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With the amount of triangles that overlap, I can't think of a way to solve this without taking a couple hours and counting them all. [/ QUOTE ] How long does it take for you to count to 84? Or how about to 28?
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#29
07-22-2005, 02:41 PM
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Re: Sister\'s math problem X-post
I think the solution is 3*(26!)
(26!) is 26+25+24+23 etc... and that answer is 1.20987438×10^27 I got that by counting all of the trianges in the top section (26) and multiplying it by 3... I could be way off...
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