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  #21  
Old 10-22-2003, 09:12 AM
Nottom Nottom is offline
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Default Re: AA vs AA

You making it way to complicated and thinking about it the wrong way. You are only concerned with how often 1 out of the other 9 people will have AA when you do, which accounts for 2 of the aces immediately (they are in your hand). The other responces in this thread already explain the math and reasoning behind the calculation, which is correct.
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  #22  
Old 10-22-2003, 09:30 AM
ropey ropey is offline
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Default Re: AA vs AA

I certainly see why its 1/136 for another player to have pocket aces when you do...

However, the odds of any two players recieving pocket aces on the same hand is 1/6016.

-ropey
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