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#1
09-19-2005, 10:06 AM
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Re: A Texas Hold \'Em game with two jokers in the deck
Ok you have the normal odds for 77 beating AA. in addition to this you also have odds the board will come with a four flush in a black suit plus the odds the the board comes down with a straight that can range from 3 to J. Any 7 on board wins it for the joker as long as an A doesn't fall. Any trips wins as long as there isn't an A.
I reckon 7-Jo is probably winning, maybe 60:40 ahead although thats a guess. What happens if a joker falls on the board? Thats got to lead to some crazy hands. 
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#2
09-19-2005, 02:26 PM
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Re: A Texas Hold \'Em game with two jokers in the deck
Joker - anything is killing all other hands.
you chop all board 4 straights, win half the 4 flushes, chop the other two, win almost anytime a 7 comes on board, win almost anytime the board pairs. I don't know how to calculate it, but I would put it at something like 70-30 for the Joker-7 vs. AA. Hell, just the joker is probably 50% vs. AA.
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