Coin Toss Challenge

[2ndGoat]

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Assume that by flipping any coin either a heads or a tails will always show. is there any way that by flipping a coin or multiple coins you can create an event with a probablilty of 1/3?

Note the odd man out method is not a true solution to this question.

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Flip the coin twice.

HH - Person 1 wins
HT - Person 2 wins
TH - Person 3 wins
TT - Begin again.

A winner will eventually be selected with probability 1. Also, in practice, it is unlikely that you'll ever have to do it more than 4 or 5 times to get a winner.

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Continues to boggle my mind that something can have a probability of one yet there is a specific way in which that outcome can fail to occur. Math is t3h r0x0rz!!!111one

2nd

[SumZero]

Right and the reason it is a special case is because the fraction 2/3 binary expansion is:

101010101010101010101.....

[Skjonne]

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Here p can be any number between 0 and 1 , even something irrational like pi.

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Did they change the value of pi without telling me? [img]/images/graemlins/smile.gif[/img]