#11
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Re: Tough brainteaser.
You are wrong.
I'll elobarate. Say you weigh AB v CD and they balance. So the outlier is E,F,G or H. According to your theory you now wiegh AB v EF. And if they balance they G or H must be the outlier. Now you weigh G against A. If they balance, then H must be the outlier. But you don't know if H is ligther of heavier than the others. You are close, but sadly no cigar. |
#12
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Re: Tough brainteaser.
Ok I see your point I'll try again...
1) First step as above to narrow the field four balls- A, B, C and D and four 'normal' balls N,N,N,N. 2) Weigh A, B, and C against 3 normal balls (!) If they are equal, D is the outlier and you use the last weighing to work out if it heavier or lighter than a normal ball. If they dont match, you know the outlier is A, B, or C ALSO you KNOW IF IT IS HEAVIER/LIGHTER THAN NORMAL! 3) Now, for the third weighing, weigh A vs B. If they are equal C is the outlier (and you know the mass). If they are unequal, because you know the mass difference of the outlier, you can identifier the outlier between A and B. Hows that? aquifex |
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