2-card Poker: +EV Hands

Forget about strategy: betting, position, blinds, etc. I'm simply looking for which hands are expected to win more than they lose. It's strictly a statistical question.

I think my original solution was actually way off. Here's my new solution:

HANDED +EV
2 [J7, AA]
3 [K2, AA]
4 [K9, AA]
5 [A2, AA]
6 [A5, AA]
7 [A7, AA]
8 [A8, AA]
9 [A9, AA]

I get exactly what you got.
I ordered all the hands from 1 to 1326 (6 slots each for pairs and 16 slots each for non-pairs). Then I just divided by the number of people in the game to find the threshold hand.

-v

[PseudoPserious]

I got a slightly different answer:
# Sim Prob(indep)
9 AJ AJ
8 AT AJ
7 A9 A9
6 A7 A8
5 A4 A5
4 A2 KQ
3 K4 K5
2 J7 J7

The Prob(indep) column is the lowest ranked hand with at least a 50% chance that all opponents will be dealt that hand or worse.

This assumes that each hand is independent, which isn't quite correct (if you have aces, there are fewer Ax hands out there, for example). So, I wrote a little sim that actually dealt hands. That's the Sim column (100,000 hands per run; 3 runs to make sure the break-even point was correct).

PP