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  #101  
Old 03-17-2005, 07:50 PM
ethan ethan is offline
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Join Date: Jun 2004
Location: los angeles
Posts: 237
Default Re: Super Duper Extra Hard Brainteaser

[ QUOTE ]
What is the probability of girl named sarah, girl?

1/200 * 1/2 which is 100/40,000

Where am I going wrong?

[/ QUOTE ]

1/200 * (99/100) * 1/2. They can't both be sarah.
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  #102  
Old 03-17-2005, 07:51 PM
DMBFan23 DMBFan23 is offline
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Join Date: Jun 2004
Location: I don\'t want a large Farva
Posts: 417
Default Re: Super Duper Extra Hard Brainteaser

jason, by that logic the answer to the first, easier, problem is 1/2, which is wrong.
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  #103  
Old 03-17-2005, 07:52 PM
partygirluk partygirluk is offline
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Join Date: Nov 2004
Location: Pwning Broken Glass Can
Posts: 2,279
Default Re: Super Duper Extra Hard Brainteaser

[ QUOTE ]
[ QUOTE ]
What is the probability of girl named sarah, girl?

1/200 * 1/2 which is 100/40,000

Where am I going wrong?

[/ QUOTE ]

1/200 * (99/100) * 1/2. They can't both be sarah.

[/ QUOTE ]

Hmm. The probability of the first child being a girl called Sarah is just 1/200 and then the probability of the next one being a girl is 1/2 n'est pas?
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  #104  
Old 03-17-2005, 07:53 PM
Patrick del Poker Grande Patrick del Poker Grande is offline
Junior Member
 
Join Date: Apr 2004
Posts: 8
Default Re: Super Duper Extra Hard Brainteaser

[ QUOTE ]
[ QUOTE ]
[ QUOTE ]
What is the probability of girl named sarah, girl?

1/200 * 1/2 which is 100/40,000

Where am I going wrong?

[/ QUOTE ]

1/200 * (99/100) * 1/2. They can't both be sarah.

[/ QUOTE ]

Hmm. The probability of the first child being a girl called Sarah is just 1/200 and then the probability of the next one being a girl is 1/2 n'est pas?

[/ QUOTE ]
Non. Read this. All of it.
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  #105  
Old 03-17-2005, 07:53 PM
partygirluk partygirluk is offline
Senior Member
 
Join Date: Nov 2004
Location: Pwning Broken Glass Can
Posts: 2,279
Default Re: Super Duper Extra Hard Brainteaser

[ QUOTE ]
jason, by that logic the answer to the first, easier, problem is 1/2, which is wrong.

[/ QUOTE ]

There are three possibilities once we know there is at least one girl:

girl, girl
boy, girl
girl, boy

Therefore the answer to the first question is 1/3
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  #106  
Old 03-17-2005, 07:53 PM
jason_t jason_t is offline
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Join Date: Nov 2004
Location: Another downswing?
Posts: 2,274
Default Re: Super Duper Extra Hard Brainteaser

[ QUOTE ]
jason, by that logic the answer to the first, easier, problem is 1/2, which is wrong.

[/ QUOTE ]

Wrong, the possibilities in the first question, once we know there is at least one girl are

G, B
B, G
G, G

and all of these are equally likely. So the answer is 1/3.
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  #107  
Old 03-17-2005, 07:54 PM
sam h sam h is offline
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Join Date: Sep 2002
Posts: 742
Default Re: Super Duper Extra Hard Brainteaser

Seems to me that this is only a brainteaser because it induces people to waste a bunch of time with the Sarah red herring when the answer is still 1/3.

Think about it intuitively: If you gathered a population of mothers with two children, at least one of which is a girl, and divided them into subpopulations based on whether they had a child named Sarah, would you expect the subpopulations to have different estimated means on the #ofGirls variable. Basically, the Sarah thing just identifies a subpopulation but shouldn't change any other characteristics.
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  #108  
Old 03-17-2005, 07:55 PM
Patrick del Poker Grande Patrick del Poker Grande is offline
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Join Date: Apr 2004
Posts: 8
Default Re: Super Duper Extra Hard Brainteaser

[ QUOTE ]
Seems to me that this is only a brainteaser because it induces people to waste a bunch of time with the Sarah red herring when the answer is still 1/3.

Think about intuitively: If you gathered a population of mothers with two children, at least one of which is a girl, and divided them into subpopulations based on whether one they had named a child Sarah, would you expect the subpopulations to have different estimated means on the #ofGirls variable. Basically, the Sarah thing just identifies a subpopulation but shouldn't change any other characteristics.

[/ QUOTE ]
Exactly.
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  #109  
Old 03-17-2005, 07:56 PM
jason_t jason_t is offline
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Join Date: Nov 2004
Location: Another downswing?
Posts: 2,274
Default Re: Super Duper Extra Hard Brainteaser

[ QUOTE ]
Seems to me that this is only a brainteaser because it induces people to waste a bunch of time with the Sarah red herring when the answer is still 1/3.

Think about intuitively: If you gathered a population of mothers with two children, at least one of which is a girl, and divided them into subpopulations based on whether one they had named a child Sarah, would you expect the subpopulations to have different estimated means on the #ofGirls variable. Basically, the Sarah thing just identifies a subpopulation but shouldn't change any other characteristics.

[/ QUOTE ]

Think about it like this, it might change your mind: knowing that a women has two girls increases the likelihood that she has a child named Sarah. Conversely, knowing she has a child named Sarah....
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  #110  
Old 03-17-2005, 07:56 PM
partygirluk partygirluk is offline
Senior Member
 
Join Date: Nov 2004
Location: Pwning Broken Glass Can
Posts: 2,279
Default Re: Super Duper Extra Hard Brainteaser

[ QUOTE ]
[ QUOTE ]
[ QUOTE ]
[ QUOTE ]
What is the probability of girl named sarah, girl?

1/200 * 1/2 which is 100/40,000

Where am I going wrong?

[/ QUOTE ]

1/200 * (99/100) * 1/2. They can't both be sarah.

[/ QUOTE ]

Hmm. The probability of the first child being a girl called Sarah is just 1/200 and then the probability of the next one being a girl is 1/2 n'est pas?

[/ QUOTE ]
Non. Read this. All of it.

[/ QUOTE ]

Please explain which part of what I said was wrong.
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