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#1
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Re: Head Up Theory Question
[ QUOTE ]
You have 9. You bet. I am acting second. I have an unexploitable strategy for the second player which involves raising the first bet with 8,9, 10 every time. How is folding a 9 ever part of a correct strategy? Enlighten me [/ QUOTE ] It's 'correct' in the usual game-theory sense: There is a pair of 'strategies' (which specify how to act in every possible situation, and may involve randomly choosen actions) call them P1 (first player's strategy) and P2 (the second) such that: 1) If I'm first player and use P1, you never get more than 8% whatever strategy you play 2) If I'm second player and use P2, I never get less than 8% whatever strategy you play It just happens that P1 does something rather odd with the second highest card. I can put the pair P1, P2 on the web so people can look at them/try to beat them if really necessary (but it wouldn't be very illuminating). P1 and P2 aren't unique. Maybe there's a P2 which behaves as you specified, I don't know. Marv |
#2
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Re: Head Up Theory Question
marv,
(If you have the time to post it) I would be interested in seeing an unexploitable P1 and P2 strategy. (You were talking about a ten card game, but if you can illustrate it with even less cards, it might be even easier to understand.) I suppose it is possible to have an unexploitable strategy, but I don't quite see what it would like yet. |
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