#11
|
|||
|
|||
Re: Another What are the Odds?
4%??? think about that, 4 out of every hundred hands? Don't you think that you would have seen this before? unless you've only played like 25 hands in your life...
|
#12
|
|||
|
|||
Re: Another What are the Odds?
[ QUOTE ]
[ QUOTE ] Are the numbers you gave already assuming Player 2 has a pocket pair as well? [/ QUOTE ] Yes. [/ QUOTE ] After thinking about this further, does it really matter that each player is holding a pocket pair? Sure it changes the odds a very small amount (since certain 4-of-a-kinds are not possible for the board) but I think the probabilities would be almost the same since both players are playing the board no matter what they hold. |
#13
|
|||
|
|||
Re: Another What are the Odds?
On the other hand. . .
Once the flop was dealt, there were 903 possible combinations of turn and river cards. Only 5-5 and A-A lost for you, and each could only happen one way. So you had 2/903 or about 0.2% chance of losing. In both cases your opponents tie. This will happen to you again. It's not likely to be quads with two opponents splitting the pot, but you'll see people pull out the only possible pair of cards that can beat you many times. |
#14
|
|||
|
|||
Re: Another What are the Odds?
[ QUOTE ]
After thinking about this further, does it really matter that each player is holding a pocket pair? Sure it changes the odds a very small amount (since certain 4-of-a-kinds are not possible for the board) but I think the probabilities would be almost the same since both players are playing the board no matter what they hold. [/ QUOTE ] I ran the numbers again for both players holding no-pair hands, with no ranks in common. It now depends on the highest hole card, rather than the highest pair. The difference is that there are now 9 ranks of quads instead of 11, and each quad gets 1 more possible kicker, since there are 3 of the highest hole card rank. New formula: { [(14-N)*4 + 3]*(N-5) + [(13-N)*4 + 3]*(14-N) } / C(48,5) That is, for each of the N-5 possible quads less than N, there are (14-N)*4 kickers greater than N, plus 3 of rank N. Then for each of the 14-N quads greater than N, there are (13-N)*4 kickers greater than N, plus 3 of rank N. <font class="small">Code:</font><hr /><pre> high hole P(split) odds-to-1 5 0.018% 5435 6 0.017% 6050 7 0.015% 6821 8 0.013% 7818 9 0.011% 9156 10 0.0091% 11046 11 0.0072% 13920 12 0.0053% 18816 13 0.0034% 29021 14 0.0016% 63418 </pre><hr /> Here are the pocket pair data again for comparison. Original formula: { [(14-N)*4 + 2]*(N-3) + [(13-N)*4 + 2]*(14-N) } / C(48,5) <font class="small">Code:</font><hr /><pre> high pair P(split) odds-to-1 33 0.027% 3705 44 0.025% 4057 55 0.022% 4481 66 0.020% 5006 77 0.018% 5669 88 0.015% 6535 99 0.013% 7712 TT 0.011% 9407 JJ 0.0083% 12057 QQ 0.0060% 16786 KK 0.0036% 27617 AA 0.0013% 77831 </pre><hr /> |
#15
|
|||
|
|||
Re: Another What are the Odds?
Very interesting.
|
Thread Tools | |
Display Modes | |
|
|