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View Poll Results: Tom Cruise's Best Movie | |||
Risky Business |
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10 | 6.29% |
Color of Money |
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14 | 8.81% |
Cocktail |
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3 | 1.89% |
Top Gun |
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35 | 22.01% |
Rainman |
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10 | 6.29% |
Days of Thunder |
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1 | 0.63% |
A Few Good Men |
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18 | 11.32% |
The Firm |
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4 | 2.52% |
Interview With A Vampire |
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4 | 2.52% |
Eyes Wide Shut |
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3 | 1.89% |
Mission: Impossible |
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2 | 1.26% |
Jerry Maguire |
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11 | 6.92% |
Magnolia |
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15 | 9.43% |
Vanilla Sky |
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6 | 3.77% |
Minority Report |
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12 | 7.55% |
The Last Saumrai |
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11 | 6.92% |
Voters: 159. You may not vote on this poll |
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#11
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[ QUOTE ] There are easier ways to make a lot of money in NL than taking 55/45 edges. [/ QUOTE ] It's easier to make even more money in NL by taking 55/45 edges. [/ QUOTE ] |
#12
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What percentage of the time would you have to be right (he does in fact have overcards) to make this play? Greater than 90%?
I'm just saying that if a player is willing to move in for 50 bets preflop with AK, there are probably easier ways to take his money then taking 58/42 with him. No? Edit: You are risking 480 to win roughly 600. 58% of the time you win 1080 (626), 42% of the time you lose 480 (201). Interesting. I recant my previous statement about not pushing if you are 100% positive, but I still fold in this circumstance. How do you do this calculation for different % levels of you being confident he has overcards, for different expectations, just curious... |
#13
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listen to the masked man then give me my name back.
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#14
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AZK you are right, elD is being pinickity and stating the theoretical obvious.
If you're 57% to win against overs, and 20% to win against overpair, then the chance of winning is: ( 57p + 20(1-p) ) / 100 = (37p + 20) / 100 where p is the chance he has overcards only. E.g. If you're 75% sure he has overs, the expression yields .475 ie -EV. (Ignoring blinds etc, which would make this about even). In an internet cash game I really dont see how anyone can be 75%+ sure villian has overs when he pushes all in in this manner. |
#15
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On another note, I have my number theory finals paper tomorrow...gone are the days of p and 1-p being probabilities....i wish. Now p is a prime ideal that most likely splits in the euclidean ring concerned causing a huge mess in all the calculations.
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#16
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Interesting. Slipped my mind about how even if he has an overpair you still win 20% of the time. I agree for the internet it's damn near impossible. I mostly play live, so after playing for a few orbits with people I usually have a pretty good idea if they are the type to push with an overpair or with overcards. I would say the intervals go something like 60%, 75%, 90% for some people. So this is why it's normally an easy fold for me...
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#17
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1. Who said this is a fold if he has two overcards? what what what?
2. It is still a fold under the cirumstances which I can see though. |
#18
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listen to the masked man then give me my name back. [/ QUOTE ] Seriously, these forums ain't big enough for the three of us. |
#19
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What percentage of the time would you have to be right (he does in fact have overcards) to make this play? Greater than 90%? [/ QUOTE ] This is a simple math problem. Don't ask me, figure it out for yourself. Don't forget to take into account the money already in the middle. |
#20
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AZK you are right, elD is being pinickity and stating the theoretical obvious. [/ QUOTE ] AZK is right? If this were so obvious, then please explain his statements. Thanks, chief. [ QUOTE ] There are easier ways to make a lot of money in NL than taking 55/45 edges. [/ QUOTE ] This is not the attitude with which to crush cash NL games. [ QUOTE ] Even if you are dead accurate and he does in fact have overcards, I still wouldn't call. Sure you are ahead, but who cares, why take 50/50 on half a buyin when you could take much better odds on more money. [/ QUOTE ] Figure out the EV for when he has two overcards. Now tell me exactly why AZK is right to fold when he knows his opponent has overcards. |
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