He is pushing any two or?

[derdo]

My answer is (c).

I always used to think the answer should be (a) but after some thinking I changed my mind.
The prob of having AK or 97 should be equal if he is pushing with two hands with 100% in this situation.
But the knowledge that we have that he is a good player and he should see this situation and should be pushing with any two is a little strict. There is no way that you can be sure that he is pushing with any two.
There could be many reasons for a good player not to push with a weak hand although it is +EV to push with any two. He could think that, the opponents are fed up and he is gonna get called, he might be just a little careless and misread the situation, he might think that you are a loose player and would call with many hands, he might be trying to make a table image etc. etc. There could be a lot of reasons.
So assuming that an opponent is pushing with any two is the extreme assumption that you can make.
So even though we might read a player to be in a position of pushing with any two,
Prob(he has AK)> Prob (he has 97) in my opinion.

Practical value to this discussion is if ICM says that calling is +EV just marginally with the assumption that your opponent is pushing with any two, it is most probably -EV to call since pushing with any two range is the extreme assumption.

That's my take on this...

[deathpotato]

If the player should be pushing any two he will not fold 97. He might fold 32, but this is all beside the point. If a situation is so marginally +EV that the removal of a few hands from the pusher's range is going to tip it over the scale to negative, you shouldn't call anyway because a) if you outchip him there is more value in the chips you lose than in the chips you win and b) if he outchips you the risk of busting (and therefore being able to make no more +EV moves in the tournament) outweighs a marginally +EV situation.

[ QUOTE ]
My answer is (c).

I always used to think the answer should be (a) but after some thinking I changed my mind.
The prob of having AK or 97 should be equal if he is pushing with two hands with 100% in this situation.
But the knowledge that we have that he is a good player and he should see this situation and should be pushing with any two is a little strict. There is no way that you can be sure that he is pushing with any two.
There could be many reasons for a good player not to push with a weak hand although it is +EV to push with any two. He could think that, the opponents are fed up and he is gonna get called, he might be just a little careless and misread the situation, he might think that you are a loose player and would call with many hands, he might be trying to make a table image etc. etc. There could be a lot of reasons.
So assuming that an opponent is pushing with any two is the extreme assumption that you can make.
So even though we might read a player to be in a position of pushing with any two,
Prob(he has AK)> Prob (he has 97) in my opinion.

Practical value to this discussion is if ICM says that calling is +EV just marginally with the assumption that your opponent is pushing with any two, it is most probably -EV to call since pushing with any two range is the extreme assumption.

That's my take on this...

[/ QUOTE ]

I think your wrong, in your first post you told us:
A.villain knows when it's correct to push any two.
B.the situation at hand warrants an any two push.
C.villain pushes.

Your implying that he should be pushing any two in this spot, you dont mention any other variables, AK=97.

a) is the correct answer.

[derdo]

hey man I am not trying to scam anybody here (big lewboski quote)
I didn't try to trick anybody...

[ QUOTE ]

A.villain knows when it's correct to push any two.
B.the situation at hand warrants an any two push.
C.villain pushes.


[/ QUOTE ]
Yes this is exactly what I have described.
I think P(AK)> P(97) for the reasons I stated in the above two posts...

[Freudian]

[ QUOTE ]
hey man I am not trying to scam anybody here (big lewboski quote)
I didn't try to trick anybody...

[ QUOTE ]

A.villain knows when it's correct to push any two.
B.the situation at hand warrants an any two push.
C.villain pushes.


[/ QUOTE ]
Yes this is exactly what I have described.
I think P(AK)> P(97) for the reasons I stated in the above two posts...

[/ QUOTE ]

That is an impossibility with the assumptions you make. You have to change your assumptions to be able to come to that conclusion.

[se2schul]

[ QUOTE ]

[ QUOTE ]

A.villain knows when it's correct to push any two.
B.the situation at hand warrants an any two push.
C.villain pushes.


[/ QUOTE ]
Yes this is exactly what I have described.
I think P(AK)> P(97) for the reasons I stated in the above two posts...

[/ QUOTE ]

Well, if that's the case, then either villain is NOT pushing any 2, or your deck contains more As and Ks than 9s and 7s.

He's either pushing ANY 2 or not. If he really is pushing any 2, then him having 23 is just as likely as 97 is just as likely as AK is just as likely as any non-pocket pair hand.