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Re: What about that third flop card ???
A longwinded, but straightforward approach is:
Say you hold 2 clubs. Then 11 clubs remain in the 50 cards left in the deck. So the probability of a club coming on the first card is 11/50. If the first card is a club, the probability of the second card being a club is 10/49. Now 9 clubs and 39 nonclubs are left in the remaining 48 cards. So the probability of the 3rd card NOT being a club is 39/48. The total probability of the cards coming in this PRECISE order is (11/50)*(10/49)*(39/48). However, the cards can come in any order. How many ways are there for three cards, 2 of which are clubs, to come? Three ways. (If C=club and X=nonclub, the possible orders are CCX, CXC, and XCC.) So P(2 and only 2 clubs on the flop)= 3*(11/50)*(10/49)*(39/48)= 0.1094 |
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