Basic omaha probability question

[BlueBear]

Hi,

I would like to calculate the probability of being dealt an omaha containing at least 2 aces or more.

The number of possible starting omaha hands = 52*51*50*49 = 52,4 C = 6497400
The number of possible hands containing at least 2 aces = 6 * 50 * 49 = 14700 (6 acccounts for all possible combinations of a pair of aces).

Probability = 14700/6497400 = 0.0021 = 0.2%

This looks too low and I'm sure I have made a mistake here. Could anybody take a look at this?

BlueBear