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Factoring fold equity percentage.
Can someone please explain the numbers in the following equation to me in detail?
let x = % time he folds. so (1-x) = times he calls 7200 in pot 9200 left in your stack Assuming 22% equity when called Then your push is EV neutral when 7200x + (1-x){(.22)(22000) - 9200} = 0 Sorry, but I am not a math guy and need it spelled out for me. In the equation above, I believe he comes up with the 22% equity because he is drawing to the nut flush on the turn. This equation came from the following thread: link Thanks |
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