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Three all-ins on a board of AQT:
Hand 1: AQ Hand 2: AT Hand 3: QT For the flop to come up AQT, the probability is 2/46 * 2/45 * 2/44 = .000087834 How do I adjust the odds of the hands to figure out the total likelyhood of the board + the hands? Is it ((4/52 * 4/51 AQ) * (3/50 * 4/49 QT) * (3/48 * 3/47 AT)) + (2/46 * 2/45 * 2/44)? Thanks! |
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