please check my math

[bosulli]

I have calculated the P of a hitting a flush draw, inside straight draw, 2 pair or trips on the flop holding cards of (6s7s).

For an inside straight draw, combinations of (4,5), (5,8) or (8,9) are needed. There are 36 pair combinations of the needed cards. There are 1,728 needed three card combinations. 19,600 possible 3 card combinations. P = 11.7%.

For 4 card flush draw [11/50*10/49*39/48*3]=10.9%. Got this from Yao King’s book “Weighing the Odds…”

For 2 pair, there are 9 combinations of (6,7), and 432 possible 3 card combinations. P=2.2%.

For trips, there are 3 combinations of (6,6) & 3 of (7,7), and 288 possible 3 card combinations. P= 1.5%.

Therefore the P of the first statement is 26.3%.

Right????