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Old 08-14-2005, 03:23 AM
OrianasDaad OrianasDaad is offline
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Join Date: Aug 2004
Posts: 476
Default EV stats and max winrate questions/observations.

I've been doing some figuring on the EV numbers over at the pokerroom website, and have found, according to their EV stats, the maximum winrate.

Here's how I got it:

I figured that if each hand had an EV, then it should follow that multiplying that EV amount in BB by the probability of getting that hand will provide an EV/100 hands.

Proabilites:
Pocket pairs: .4525
Suited: .1508
Offsuit Non-Pair: .6033

For instance, KQs is listed with an EV of 0.39. You'll get this hand .15% of the time. .39 * .15 = .0588. That's how much this hand is worth towards the theoretical "maximum" winrate.

This magical theoretical figure, by-the-way is about 4.87 BB/100.

My questions are:

- How reliable are the numbers at pokerroom?
- Even if the stats are only close to a "true" EV for each hand, the total theoretical winrate can't be much different can it?
- Did I even do this right?
- These stats at pokerroom do include the blinds, correct?
- Assuming these number do not include the blinds and they are theoretically correct, doesn't that make this game unbeatable? I personally believe that if this is the case, then limit HE is unbeatable. Thankfully, I'm fairly certain that pokerroom's EV calculations have included the blinds.
- Since I didn't do each of these hands by position (just overall), will this winrate change signifigantly when I only include hands when they are profitable at a certain position?
- I noticed that some offsuit hands that have less EV are worth more to the overall BB/100 than suited hands, due to frequency. Just an interesting observation.
- Adding the frequency of hands that are either +EV or null EV, it comes to a mere 13.25%. Does this mean that players who have a higher VPIP than this (outside the blinds) are either "tricky", playing hands for their relative and/or positional value?

Answer any or all. Please discuss.
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