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Probability of one OR more person getting dealt hands XX-YY
Hi I am working on a chart and I was wondering how to calculate the following question.
If I have JJ there are 19 out of 1225 hands that call my all in if they could see my cards. Therefore, headsup, there is a 19/1225 chance that someone calls me. If there are 2 people behind me, what are the odds that one OR both people have one of those 19 hands? Remember, while there are 6 possible combinations of AA, if one person has AA, the other person can only get Aces of a different suit. Could someone give me a general equation for: X=number of hands that call me (it would be soemthing out of 1225) Y = number of players still to act behind me Z = probability of someone (one or more) getting a hand that calls me. Thank you for your time. -vqchuang |
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