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A question about Standard deviation
I looked at my 6-max SD, it is about 17BB/100 hands. Other posters report similar numbers (I saw 15-20BB/100)
Now what if I calculate SD/2 hands. The maximum I can win in a hand is 60BB, the maximum I can lose in a hand is 12BB. So, a maximum SD in 2 hands would be 72BB/2 hands, right? Now, to calculate maximum SD/100 hands, I would take max SD/2 hands and divide it by square root of 50, right? If this is right, I come up with a maximum SD of less than 11BB/100. But it is less than my actual SD of 17BB/100. How can this be? Where did I make an error? |
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