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Not exactly probability but,
how many starting hands are possible in omaha if suits are not taken into account (like how they are listed in PTOmaha)? So that A [img]/images/graemlins/spade.gif[/img] A [img]/images/graemlins/diamond.gif[/img] 2 [img]/images/graemlins/spade.gif[/img] 3 [img]/images/graemlins/diamond.gif[/img] and A [img]/images/graemlins/heart.gif[/img] A [img]/images/graemlins/club.gif[/img] 2 [img]/images/graemlins/heart.gif[/img] 3 [img]/images/graemlins/club.gif[/img] are counted as the same hand. Im not familiar with this kind of math, but my initial guesses were: 13*12*11*10 or 13^4 but i really am not sure. If you do know how to figure this out, could you please explain it for me. Thanks in advance cielo |
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