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Old 02-23-2005, 06:51 AM
donkeyradish donkeyradish is offline
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Join Date: Jun 2004
Location: Ireland
Posts: 244
Default Being dealt A2xx in Omaha/8

How do you go about calculating this probability?

ie. Chance of being dealt both at least one ace and at least one deuce in 4 cards.

My real-life results are 6.5% but I can't figure out how to calculate the true probability.

And how would you extend this for example, to calculate the odds of being dealt A23x? It sounds like it should be easy but I'm not sure where to begin.
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